Division Practice problems

Introduction to division practice problems:

In mathematics, especially in elementary arithmetic, division (÷) is the arithmetic operation that is the inverse of multiplication.

The following division methods are all based on the form Q = N / D where

• Q = Quotient

• N = Numerator (dividend)

• D = Denominator (divisor).

Specifically, if c times b equals a, written:

c x b = a

Where b is not zero, then a divided by b equals c, written:

a / b = c

In the above expression, a is called the dividend, b the divisor and c the quotient. (Source: Wikipedia)

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Example problems on division practice


Ex:1  Jack built a tower of blocks forty-five inches high. Each block in the tower is five inches tall. How many blocks were used to build the tower?

Sol: Jack built a tower of blocks forty-five inches high.

Each block in the tower is five inches tall.

So, total blocks = 45 / 5

Therefore total blocks used to build the tower = 9 blocks

Ex:2 The school's Internet connection transferred thirty six megabytes of data in six seconds. How many megabytes can it transfer in just one second?

Sol:

The school's Internet connection transferred thirty six megabytes Data in six seconds.

So, therefore total megabytes can it transfer in just one second

= 36 / 6 = 6 megabytes.

Ex:3 There are eight soft drink machines in the university. They hold sixty - four cases of soda altogether. How many cases does each machine hold?

Sol:

There are eight soft drink machines in the university.

They hold sixty - four cases of soda altogether.

Total cases of soda machine hold = 64 / 8

= 8 Cases of soda

Ex:4 Zachary used five thousand, five hundred forty-four chips to make a big batch of giant chocolate chip cookies. Each cookie got about eighteen chips. How many cookies did Zachary make?

Sol:

Zachary used five thousand, five hundred forty-four chips to make a big batch of giant chocolate chip cookies

Each cookie got about eighteen chips

So, total cookies Zachary make = 5544 / 18

= 308 Cookies

Ex:5 Twenty-five busses brought a total of seven hundred fifty passengers to the city. About how many passengers were on each bus?

Sol:

Twenty-five busses brought a total of seven hundred fifty passengers to the city.

So, total passengers were on each bus = 750 / 25

= 30 Passengers 

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Division practice problems:


Ex:1 There are thirty apartments in that building. The building has five stories. How many apartments does each story of the building have?

Ans: 6 apartments

Ex:2 Jenna will mail out seven copies of her resume on special paper. She needs twenty-eight sheets of the paper. How many pages long is her resume?

Ans: 4 pages

Ex:3 Jeremy has twenty-four balloons. He wants to give each of his four friends an equal number. How many balloons should each friend be given?

Ans: 6 balloons

Practice Act Question

Act Test preparation:

Act test is one of test which is used to get admissions in mid east countries. Depending on the test marks students get admissions in mid east colleges. Many students around the globe are writing this test hence this test mark is now accepted in US countries also. Act test is some what different from sat test. Act test consists of science reasoning questions but sat test does not. The grammatical talent of the student is checked in the act test while it is not in the sat test. Both the sat and act test are skill oriented test.  The act test is conducted for nearly 4 hrs and optional of 30 minutes.

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Act practice problems:

Act practice question 1:

Anand's new job comes with a salary increase of 8%. If he currently makes $74,000 per year, which of the following is the amount he will earn per year at his new job?

A. $79,000
B. $72,000
C. $79,200
D. $75,550
E. $79,920

Solution:

Increase percent in salary = 8 %

8% of $74,000                     = (8 x 74,000) / 100

= 8 x 740

= $5920

The total amount her earned is = $74,000 + $5920

= $79,920

The amount he earned is $79,920

Answer: E



Act practice question 2:

If Suresh biked 10 miles in 4 hours and arun biked three times as much in half the time, what was arun's average rate of speed?



A. 10 mph
B. 12 mph
C. 15 mph
D. 23 mph
E. 27 mph

Solution:

Let the speed of suresh per hour = x

Speed of arun                              = 3x

Arun biked suresh distance in ½ hour.

Total distance covered by arun   = 3*10

= 30 miles

Arun covered the distance in half the time of suresh,

= 30/2

Average speed of arun                  = 15 miles/hr

The answer is 15 miles/hr

Answer: C


Practice act questions:


Practice question 1:

In an urn there are 15 balls: 8 balls are black, 4 are red and 3 are orange. Then 1 black and 1 red ball are taken from the urn and put away. What is the probability that a red ball is selected at random from the urn?

A) 3/13
B) 5/15
C) 6/15
D) 7/13
E) 4/13

Answer: A

Practice question 2:

A group of 7 friends are having dinner together. Each person eats at least 3/4 of a cake. What is the smallest number of whole cakes needed for dinner?

A) 7
B) 5
C) 6
D) 28
E) 21

Answer: C

Reasoning Practice Test

Introduction:

Let us learn about the reasoning practice test. Reasoning test is a test which is conducted to get placed in international colleges, universities and in companies. Reasoning test  practice consists of quantitative aptitude, verbal reasoning and analytical writing. Quantitative aptitude involves math problem solving questions on various topics. Practice of reasoning test questions helps the students to get skilled in aptitude questions. It also helps the students to get prepared for SAT and ACT test.

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Reasoning practice test:


Example 1:

A trader mixes 30 kg of rice at Rs. 18 per kg with 28 kg of rice of other variety at Rs. 34 per kg and sells the mixture at Rs. 32 per kg. What is the profit percentage?

Solution:

Total price of 58kg mixture rice = ( 30 x 18 + 28 x 34)

= 540 + 952

= Rs 1492.

Sell price of 58 kg rice = (58 x 32)

= Rs 1852

Total gain amount        = Rs 1852 - Rs 1492

= Rs 360

Total gain percentage = (360/1492)*100

= 0.24 * 100

= 24%

The profit gain is 24%



Example 2:

Vinay has 100 kg of wheat, part of wheat which he sells at 8% profit and the rest of wheat at 18% profit. He gains 14% on the whole. What is the quantity sold at 18% profit?

Solution:

From the given data, form two equations,

Part of wheat sold at 8%    = X

Part of wheat sold at 18%  = Y

X + Y = 100  equation 1

0.08X + 0.18Y = 100(0.14)

0.08X + 0.18Y = 14 equation 2

Multiply equation 1 with 0.18

0.18X + 0.18Y = 18  equation 1

0.08X + 0.18Y = 14  equation 2     (subtract)

0.10X                = 4

Divide 0.10 on both sides,

0.10X/0.10 = 4/0.10

X = 40 kg

Total quantity            = 100

Remaining quantity = 100 - 40

Y  = 60 kg

The quantity which is sold at  18% profit is 60 kg.

Practice questions:


Practice problem 1:

The ratio between the speeds of two trains is 6 : 8. If the second train runs 300 km in 3 hours, then the speed of the first train is:

A) 60 km/hr

B) 65 km/hr

C) 75km/hr

D) 73 km/hr

Answer: Option C



Practice problem 2:

544, 509, 474, 439, ... Find the next number in the given series.

A) 420

B) 404

C) 454

D) 528

Answer: Option B



Practice problem 3:

201, 202, 204, 207, ... Find the next number in the given series.

A) 211

B) 212

C) 225

D) 230

Answer: Option A

Practice 9th Grade Algebra Midterm

Introduction to practice algebra problem for 9th grade midterm:

Algebra which is fetched by a finite number which is used to define the following operations like exponents, adding the values, subtracting the values, multiplying and dividing as well.
Basically algebra midterm defines about the number systems , and here in 9th grade we can see about the following methods. They are,
Numbers

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In number systems, we can see the operations of fractions,exponents,basic arithmetic operations and place values.
Measurement:

Measurement is a process of measuring the object or shapes values in the required units.
Geometry:

Geometry is a process,in which we can declare the different shapes of polygons like regular shapes and irregular shapes.
Algebra / pattern and Probability.

Algebra pattern is a method of arranging the algebraic values in the proper order and it performs a prominent role in algebra terms.

practice problem for 9th grade algebra midterm


Example 1:

Solve the  practice algebraic problem 5(-5x - 2) - (-x - 6) = -6(4x - 5) -36

Solution:

Given the equation

5(-5x - 2) - (-x - 6) = -6(4x - 5) - 36

Multiply factors.
-25x - 10 + x + 6 = -24x + 30-36

Grouping the terms.

-24x - 4 = -24x - 4

Add 24x +4 to both sides, the above equation becomes

0 = 0

All real values are solution to this equation.

Example 2:

Simplify the  practice algebraic expression    3(a -4) + 6b - 3(a -b -2) + 8

Solution:

Given the algebraic expression

3(a -4) + 6b - 3(a -b -2) + 8

Multiply factors.

= 3a - 12 + 6b -3a + 3b + 6 + 8

Grouping the above terms.

= 9b + 2.

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Practice algebra problem for 9th grade midterm:


Try to solve this practice 9th grade algebra midterm problem:  a+ b = 3, b + c = –5, c + a = 2.

(solution: a = 5, b = -2, c = -3)

Trigonometry Practice Questions

Introduction to trigonometry practice questions:

The branch of mathematics which deals with the relations of the sides and angles of triangles, which the methods of deducing from certain given parts other required parts, and also of the general relations which exist between the trigonometrical functions of arcs or angles with the trigonometric functions.


Solved problems on trigonometry practice questions


1. Solve the trigonometric equation and find the (6 tan^2 x - 2) (2 tan^2 x - 6) = 0

2. Solve the trigonometric equation and find the interval [0 , 2Pi).

-2 sec^2 x + 4 = -2sec x

3. Solve the trigonometric equation and find the interval [0 , 2Pi).

2sin (x) cos (-x) = 2 sin (-x) sin (x)

4. Two tennis players stand on opposite sides of a net. When the ball is directly above the net, at a height of 7m above the ground, the angle of elevation from player A's position to the ball is 41±  and the angle of elevation from player B's position to the ball is 53±. What is the distance between player A and player B?

5. A pilot flying at an altitude of 1200 feet’s is starting his approach. He is 2400 feet along his flight path from the runway. What is his horizontal distance x from the runway and what is his angle of approach µ?

6. The distance between two points on the map is 5 cm correct to the nearest centimeter.

(a) Write down the

(i) Least upper bound of the measurement

(ii) Greatest lower bound of the measurements

(b) The scale of the map is 1 to 20 000. Work out the actual distance in real life (in kilometers) between the upper and lower bounds.

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7. The temperature from the factory furnace a varies inversely as the square of the distance from the furnace.

The temperature 2 meters from the furnace is 50 degrees Celsius.

Calculate the temperature 3.5 meters from the furnace. Give your answer to 2 decimal places.

Fourth Grade Free Math

Introduction of fourth grade free math:-

In Internet or website is the best place for study free fourth grade math. The students learn number of skills in math website and to work practice problems and homework problems. It is more helpful for students to improve our practice skills. In year 4 is based on fourth grade. The fourth grade student’s does on math regular basis. In number of  websites have a special tutoring service to provide math worksheets, practice problems and homework problems. The parents to teach our children’s it is also help our children’s homework problem.

Lessons in fourth grade free math:-


In the following topics involves the fourth grade free math

Number sense
Addition
Subtraction
Multiplication
Division
Algebra

Number sense

In fourth grade free math number sense is nothing but converting the numbers into wordings or converting the wordings into numbers.

For example,

2250 = Two thousand and fifty

Addition

In fourth grade free math adding the two are more value is called the addition by using the (+) operator sign.

For example,

114 + 22 = 136

Subtraction

In fourth grade free math subtract the two are more value is called the subtraction by using the (-) operator sign.

For example,

57 - 41 = 16

Multiplication

In fourth grade free math multiply the two are more value is called the multiplication by using the (x) operator sign.

For example,

134 x 13 =1742

Division

In fourth grade free math divide the two are more value is called the Division by using the (`-:` ) operator sign.

For example,

235 `-:` 21 = 11.19

Algebra

In fourth grade free math algebra is nothing but the study of operations and relations.

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Practice problems for fourth grade free math:-


Problem 1:-

Solve the number sense problem 8739.

Answer: Eight thousand seven hundred and thirty nine.

Problem 2:-

Solve the addition operation 326+45.

Answer: 371

Problem 3:-

Solve the subtraction operation 122 - 13.

Answer: 109

Problem 4:-

Solve the multiplication operation 212 x 46.

Answer: 9752.

Problem 5:-

Solve the division operation 50 `-:` 4.

Answer: 12.5

Problem 6:-

Find algebra without identity 15 x 14.

Answer: 200

Practice Algebra Division

Introduction of practice algebra division:

Algebra is a branch of mathematics, which is used to make mathematical problems of real-world events and switch problems that we cannot explain using arithmetic.

Algebra is used the symbols for addition, subtraction, multiplication and division and it includes constants, operating symbols and variables

Division is one of the arithmetic operation. Manually division is defined as the reverse operation of multiplication. Variables and constants are combined or grouped and to make algebraic expressions .it contains variables, expressions, terms, polynomials, and equation .

Main goal of division is minimizing the value of dividend or series of subtraction from dividend. The symbol for division is “/”.

Ex :     x ^2+6x+`7/x` +8


Operations of Algebra division:


The Algebra division is defined as repeated subtraction of divisor from the dividend.

The Form of Manual division method,

a / b = c

Where, a is called as  dividend. b is called as divisor.c is called as quotient.

Example:

45 / 5 = 9

example of algebra division using polynomial:

x ^2+12x+27 /  x+9

Here, x ^2+12x+27 is dividend

x+9 is divisor

x+3 is quotient of (x ^2+12x+27) / ( x+9)

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Example problems:


Division of: (x ^2+4x+6)/(x+5)

Sol:   (x ^2+4x+6) is dividend and (x+5) is the divisor.

This is the given standard form of algebra division. In first we can check the order of terms on both dividend and divisor. If it was not in degree of  order, we can arrange the terms.

Like x ^2+x+x3 mean we can change x^3+x ^2+x

After rearrange the terms we can  divide the first term of the dividend   by the first term of the divisor, it mean x ^2/x=x .It gives the first terms of quotient.

After we got the first terms of quotient, and then multiply the first term with quotient after  then subtract this product from the dividend.

The product is x ^2+5,and the subtracted value is –x+6 (remainder)

Again we can  divide the first term of the dividend   by the first term of the divisor, it mean   -x/x =-1 .

It gives the second terms  after then multiply the first term with quotient after  then subtract this product from the dividend .

Now got the remainder is 11

Final answer is x-1